foo(*bar)();This could mean that bar is a pointer to a function returning foo, or it could mean that foo is a function taking bar as a parameter and returning a function pointer. A trickier case is foo(*bar(baz))[5]. Depending on the context, this can be read either as a function declaration or as an expression involving two function calls.
'ParametricGeometry': () = {
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None of this has worked. The biggest for-profit publishers continue making more money year after year. “Diamond” open access journals—that is, publications that don’t charge authors or readers—only account for ~10% of all articles.3 Four years after that massive pledge, 38% of signers had broken their promise and published in an Elsevier journal.4。业内人士推荐旺商聊官方下载作为进阶阅读
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