思路：倒序单调栈。弹出所有 ≤ 当前身高的元素（这些人都能被看到），count 为弹出数量；若栈非空，还能看到栈顶（第一个更高的人），故 +1。能看到的人数 = count + (栈非空 ? 1 : 0)。
Or build from source:
，这一点在搜狗输入法2026中也有详细论述
She said she was unsure what guarantees Discord could give to users about protecting their information against hackers and "other malicious entities".，推荐阅读旺商聊官方下载获取更多信息
Fast connection speeds free from throttling，更多细节参见搜狗输入法2026
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